Optimal. Leaf size=177 \[ -\frac{\text{Si}\left (2 \tan ^{-1}(a x)\right )}{2 a^4 c^3}+\frac{\text{Si}\left (4 \tan ^{-1}(a x)\right )}{a^4 c^3}-\frac{x}{2 a^3 c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)^2}+\frac{x}{2 a^3 c^3 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)^2}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}+\frac{2}{a^4 c^3 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)} \]
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Rubi [A] time = 0.642054, antiderivative size = 177, normalized size of antiderivative = 1., number of steps used = 25, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {4964, 4932, 4970, 4406, 12, 3299, 4968, 4902} \[ -\frac{\text{Si}\left (2 \tan ^{-1}(a x)\right )}{2 a^4 c^3}+\frac{\text{Si}\left (4 \tan ^{-1}(a x)\right )}{a^4 c^3}-\frac{x}{2 a^3 c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)^2}+\frac{x}{2 a^3 c^3 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)^2}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (a^2 x^2+1\right ) \tan ^{-1}(a x)}+\frac{2}{a^4 c^3 \left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)} \]
Antiderivative was successfully verified.
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Rule 4964
Rule 4932
Rule 4970
Rule 4406
Rule 12
Rule 3299
Rule 4968
Rule 4902
Rubi steps
\begin{align*} \int \frac{x^3}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^3} \, dx &=-\frac{\int \frac{x}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^3} \, dx}{a^2}+\frac{\int \frac{x}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^3} \, dx}{a^2 c}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{\int \frac{1}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx}{2 a^3}+\frac{3 \int \frac{x^2}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx}{2 a}-\frac{2 \int \frac{x}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)} \, dx}{a^2 c}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}+\frac{1}{2 a^4 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{3 \int \frac{1}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)^2} \, dx}{2 a^3}+\frac{2 \int \frac{x}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)} \, dx}{a^2}-\frac{2 \operatorname{Subst}\left (\int \frac{\cos (x) \sin (x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}+\frac{3 \int \frac{1}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)^2} \, dx}{2 a^3 c}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}+\frac{2}{a^4 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}+\frac{6 \int \frac{x}{\left (c+a^2 c x^2\right )^3 \tan ^{-1}(a x)} \, dx}{a^2}+\frac{2 \operatorname{Subst}\left (\int \frac{\cos ^3(x) \sin (x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}-\frac{2 \operatorname{Subst}\left (\int \frac{\sin (2 x)}{2 x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}-\frac{3 \int \frac{x}{\left (c+a^2 c x^2\right )^2 \tan ^{-1}(a x)} \, dx}{a^2 c}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}+\frac{2}{a^4 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{\operatorname{Subst}\left (\int \frac{\sin (2 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}+\frac{2 \operatorname{Subst}\left (\int \left (\frac{\sin (2 x)}{4 x}+\frac{\sin (4 x)}{8 x}\right ) \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}-\frac{3 \operatorname{Subst}\left (\int \frac{\cos (x) \sin (x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}+\frac{6 \operatorname{Subst}\left (\int \frac{\cos ^3(x) \sin (x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}+\frac{2}{a^4 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{\text{Si}\left (2 \tan ^{-1}(a x)\right )}{a^4 c^3}+\frac{\operatorname{Subst}\left (\int \frac{\sin (4 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{4 a^4 c^3}+\frac{\operatorname{Subst}\left (\int \frac{\sin (2 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{2 a^4 c^3}-\frac{3 \operatorname{Subst}\left (\int \frac{\sin (2 x)}{2 x} \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}+\frac{6 \operatorname{Subst}\left (\int \left (\frac{\sin (2 x)}{4 x}+\frac{\sin (4 x)}{8 x}\right ) \, dx,x,\tan ^{-1}(a x)\right )}{a^4 c^3}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}+\frac{2}{a^4 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{\text{Si}\left (2 \tan ^{-1}(a x)\right )}{2 a^4 c^3}+\frac{\text{Si}\left (4 \tan ^{-1}(a x)\right )}{4 a^4 c^3}+\frac{3 \operatorname{Subst}\left (\int \frac{\sin (4 x)}{x} \, dx,x,\tan ^{-1}(a x)\right )}{4 a^4 c^3}\\ &=\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)^2}-\frac{x}{2 a^3 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)^2}+\frac{2}{a^4 c^3 \left (1+a^2 x^2\right )^2 \tan ^{-1}(a x)}-\frac{3}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{1-a^2 x^2}{2 a^4 c^3 \left (1+a^2 x^2\right ) \tan ^{-1}(a x)}-\frac{\text{Si}\left (2 \tan ^{-1}(a x)\right )}{2 a^4 c^3}+\frac{\text{Si}\left (4 \tan ^{-1}(a x)\right )}{a^4 c^3}\\ \end{align*}
Mathematica [A] time = 0.233105, size = 72, normalized size = 0.41 \[ \frac{\frac{a^2 x^2 \left (\left (a^2 x^2-3\right ) \tan ^{-1}(a x)-a x\right )}{\left (a^2 x^2+1\right )^2 \tan ^{-1}(a x)^2}-\text{Si}\left (2 \tan ^{-1}(a x)\right )+2 \text{Si}\left (4 \tan ^{-1}(a x)\right )}{2 a^4 c^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.069, size = 90, normalized size = 0.5 \begin{align*} -{\frac{8\,{\it Si} \left ( 2\,\arctan \left ( ax \right ) \right ) \left ( \arctan \left ( ax \right ) \right ) ^{2}-16\,{\it Si} \left ( 4\,\arctan \left ( ax \right ) \right ) \left ( \arctan \left ( ax \right ) \right ) ^{2}+4\,\cos \left ( 2\,\arctan \left ( ax \right ) \right ) \arctan \left ( ax \right ) -4\,\cos \left ( 4\,\arctan \left ( ax \right ) \right ) \arctan \left ( ax \right ) +2\,\sin \left ( 2\,\arctan \left ( ax \right ) \right ) -\sin \left ( 4\,\arctan \left ( ax \right ) \right ) }{16\,{c}^{3}{a}^{4} \left ( \arctan \left ( ax \right ) \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{a x^{3} -{\left (a^{2} x^{4} - 3 \, x^{2}\right )} \arctan \left (a x\right ) + \frac{2 \,{\left (a^{6} c^{3} x^{4} + 2 \, a^{4} c^{3} x^{2} + a^{2} c^{3}\right )}{\left (5 \, a^{2} \int \frac{x^{3}}{a^{6} x^{6} \arctan \left (a x\right ) + 3 \, a^{4} x^{4} \arctan \left (a x\right ) + 3 \, a^{2} x^{2} \arctan \left (a x\right ) + \arctan \left (a x\right )}\,{d x} - 3 \, \int \frac{x}{a^{6} x^{6} \arctan \left (a x\right ) + 3 \, a^{4} x^{4} \arctan \left (a x\right ) + 3 \, a^{2} x^{2} \arctan \left (a x\right ) + \arctan \left (a x\right )}\,{d x}\right )} \arctan \left (a x\right )^{2}}{a^{2} c^{3}}}{2 \,{\left (a^{6} c^{3} x^{4} + 2 \, a^{4} c^{3} x^{2} + a^{2} c^{3}\right )} \arctan \left (a x\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] time = 1.74747, size = 799, normalized size = 4.51 \begin{align*} -\frac{2 \, a^{3} x^{3} -{\left (2 i \, a^{4} x^{4} + 4 i \, a^{2} x^{2} + 2 i\right )} \arctan \left (a x\right )^{2} \logintegral \left (\frac{a^{4} x^{4} + 4 i \, a^{3} x^{3} - 6 \, a^{2} x^{2} - 4 i \, a x + 1}{a^{4} x^{4} + 2 \, a^{2} x^{2} + 1}\right ) -{\left (-2 i \, a^{4} x^{4} - 4 i \, a^{2} x^{2} - 2 i\right )} \arctan \left (a x\right )^{2} \logintegral \left (\frac{a^{4} x^{4} - 4 i \, a^{3} x^{3} - 6 \, a^{2} x^{2} + 4 i \, a x + 1}{a^{4} x^{4} + 2 \, a^{2} x^{2} + 1}\right ) -{\left (-i \, a^{4} x^{4} - 2 i \, a^{2} x^{2} - i\right )} \arctan \left (a x\right )^{2} \logintegral \left (-\frac{a^{2} x^{2} + 2 i \, a x - 1}{a^{2} x^{2} + 1}\right ) -{\left (i \, a^{4} x^{4} + 2 i \, a^{2} x^{2} + i\right )} \arctan \left (a x\right )^{2} \logintegral \left (-\frac{a^{2} x^{2} - 2 i \, a x - 1}{a^{2} x^{2} + 1}\right ) - 2 \,{\left (a^{4} x^{4} - 3 \, a^{2} x^{2}\right )} \arctan \left (a x\right )}{4 \,{\left (a^{8} c^{3} x^{4} + 2 \, a^{6} c^{3} x^{2} + a^{4} c^{3}\right )} \arctan \left (a x\right )^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{x^{3}}{a^{6} x^{6} \operatorname{atan}^{3}{\left (a x \right )} + 3 a^{4} x^{4} \operatorname{atan}^{3}{\left (a x \right )} + 3 a^{2} x^{2} \operatorname{atan}^{3}{\left (a x \right )} + \operatorname{atan}^{3}{\left (a x \right )}}\, dx}{c^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{3}}{{\left (a^{2} c x^{2} + c\right )}^{3} \arctan \left (a x\right )^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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